Math  /  Algebra

QuestionFind the wavelength (λ)(\lambda) in meters of a photon with energy 4.87×1020 J4.87 \times 10^{-20} \mathrm{~J}.

Studdy Solution
Calculate the wavelength of the photon.
λ=(6.626×1034 Js)(3.00×108 m/s)/(4.87×1020 J)=4.08×107 m\lambda = (6.626 \times10^{-34} \mathrm{~J \cdot s}) \cdot (3.00 \times10^{8} \mathrm{~m/s}) / (4.87 \times10^{-20} \mathrm{~J}) =4.08 \times10^{-7} \mathrm{~m}The wavelength of the photon is 4.08×107 m4.08 \times10^{-7} \mathrm{~m}.

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