QuestionThe electric field intensity in polystyrene with $\epsilon_{r}=2.55$ , filling the space between the plates of a parallel capacitor is $10 \mathrm{KV} / \mathrm{m}$ . The distance between the plates is 1.55 mm . Calculate: - $\quad D$ and $P$ - The surface charge density of free charge on the plates. - The surface density of polarization charge. - The potential difference between the plates.

Studdy Solution
Calculate the potential difference between the plates.
The potential difference $V$ is given by:
$V = E \cdot d$
where $d = 1.55 \, \text{mm} = 1.55 \times 10^{-3} \, \text{m}$ .
Substitute the values:
$V = 10 \times 10^{3} \times 1.55 \times 10^{-3}$

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