Math  /  Trigonometry

QuestionThe cosine graph shown has a range [3,9][-3,9]. The graph has an equation in the form y=acos[b(xc)]+d,a>0y=a \cos [b(x-c)]+d, a>0. Determine the equation if the graph has a minimum possible phase shift. max =9=9 min =5=-5 y=acos[b(xc)]+da=maxmin2d=max+min2a=4(3)2d=9+(3)2a=6a=3\begin{array}{l} y=a \cos [b(x-c)]+d \\ a=\frac{\max -\min }{2} \quad d=\frac{m_{a x}+\min }{2} \\ a=\frac{4-(-3)}{2} \quad d=\frac{9+(-3)}{2} \\ a=6 \\ a=3 \end{array} y=6cos[b(xc)]+3y=6 \cos [b(x-c)]+3

Studdy Solution
Putting it all together, our equation is: y=6cos[2(xπ/2)]+3 y = 6 \cos[2(x - \pi/2)] + 3

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