Math  /  Data & Statistics

QuestionThe central angle of sector UU is 9090^{\circ}. What is the probability that the spinner lands on UU ?
Simplify your answer and write it as a proper fraction.

Studdy Solution
Simplify the fraction:
90360=14 \frac{90}{360} = \frac{1}{4}
The probability that the spinner lands on sector UU is:
14 \boxed{\frac{1}{4}}

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