QuestionTatenda has a circle with an equation $x^{2}+y^{2}-8 x+4 y+4=0$. Find the coordinates of the centre of this circle.

Studdy Solution
Identify the coordinates of the center from the standard form of the circle equation, $(x - h)^2 + (y - k)^2 = r^2$.
From the equation $(x - 4)^2 + (y + 2)^2 = 16$, we can see that the center $(h, k)$ is $(4, -2)$.
The coordinates of the center of the circle are $(4, -2)$.