Math  /  Trigonometry

Questiontan1(1.53)=cos1(2.26)=sin1(0.42)=\begin{array}{c}\tan ^{-1}(-1.53)= \\ \cos ^{-1}(2.26)= \\ \sin ^{-1}(0.42)=\end{array}

Studdy Solution
Evaluate sin1(0.42)\sin^{-1}(0.42):
- The sin1\sin^{-1} function is defined for values in the range [1,1][-1, 1]. - The result is an angle in the range [π2,π2][- \frac{\pi}{2}, \frac{\pi}{2}]. - Use a calculator or trigonometric tables to find the angle whose sine is 0.420.42.
The evaluated values are: - tan1(1.53)\tan^{-1}(-1.53) is approximately 0.993-0.993 radians (or 56.9-56.9^\circ). - cos1(2.26)\cos^{-1}(2.26) is undefined. - sin1(0.42)\sin^{-1}(0.42) is approximately 0.4330.433 radians (or 24.824.8^\circ).

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