Math / Discrete

QuestionSuppose two dice (one red, one green) are rolled. Consider the following events. $A$ : the red die shows $4 ; B$ : the numbers add to $2 ; C$ : at least one of the numbers is 4 ; and $D$ : the numbers do not add to 8 . Express the given event in symbolic form.
The numbers do not add to 2 . B D $D^{\prime}$ $B^{\prime}$ $B^{\prime} \cup D$
How many elements does it contain? $\square$

Studdy Solution
To find the number of elements in $B'$ , we first find the total number of possible outcomes when rolling two dice, which is $6 \times 6 = 36$ .
Since $B$ contains only one element, $B'$ contains all the other outcomes.
Therefore, the number of elements in $B'$ is $36 - 1 = 35$ .
The number of elements in $B'$ is:
$\boxed{35}$

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