Math  /  Algebra

QuestionSuppose that f(x)=6x1f(x)=6 x-1 and g(x)=3x+8g(x)=-3 x+8 (a) Solve f(x)=0f(x)=0. (b) Solve f(x)>0f(x)>0. (c) Solve f(x)=g(x)f(x)=g(x). (d) Solve f(x)g(x)f(x) \leq g(x). (e) Graph y=f(x)y=f(x) and y=g(x)y=g(x) and find the point that represents the solution to the equation f(x)=g(x)f(x)=g(x). (a) For what value of xx does f(x)=0f(x)=0 ? x=16x=\frac{1}{6} (Type an integer or a simplified fraction.) (b) For which values of x is f(x)>0\mathrm{f}(\mathrm{x})>0 ? (16,)\left(\frac{1}{6}, \infty\right) (Type your answer in interval notation. Use integers or fractions for any numbers in the expression.) (c) For what value of xx does f(x)=g(x)f(x)=g(x) ? x=1x=1 (Type an integer or a simplified fraction.) (d) For which values of xx is f(x)g(x)f(x) \leq g(x) ? \square (Type your answer in interval notation. Use integers or fractions for any numbers in the expression.)

Studdy Solution
Graph y=f(x) y = f(x) and y=g(x) y = g(x) to find the intersection point.
The intersection point of the lines y=6x1 y = 6x - 1 and y=3x+8 y = -3x + 8 is at x=1 x = 1 .
The corresponding y y -value is:
y=6(1)1=5 y = 6(1) - 1 = 5
So, the intersection point is (1,5) (1, 5) .

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