Math  /  Algebra

Questionk=1n(bk9ak)\sum_{k=1}^{n}\left(b_{k}-9 a_{k}\right) where ak=7a_k = 7 and bk=30b_k = 30.

Studdy Solution
Evaluate the summation k=1n(33)\sum_{k=1}^{n} (-33):
Since 33-33 is a constant, the summation simplifies to:
k=1n(33)=33×n \sum_{k=1}^{n} (-33) = -33 \times n
The final result of the summation is 33n-33n.

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