QuestionStation 4:
1. $x+4 y=2,3 y+x=10$ 2. $$\begin{array}{l} (3 y+x)-(x+4 y)=10-2 \\ 3 y+x-x-4 y=8 \\ y=-8 \\ x+4(-8)=2 \\ x-32=2 \\ x=34 \end{array}$$

Studdy Solution
Verify the solution by substituting $x = 34$ and $y = -8$ back into the original equations.
For the first equation:
$34 + 4(-8) = 2$
Simplify:
$34 - 32 = 2$
$2 = 2 \quad \text{(True)}$
For the second equation:
$3(-8) + 34 = 10$
Simplify:
$-24 + 34 = 10$
$10 = 10 \quad \text{(True)}$
Both equations are satisfied.
The solution is $x = 34$ and $y = -8$.