Math  /  Data & Statistics

Questionwww-awualeks.com Content Aleks Blackboard Content Session Clo... Content Jonathan V-. \mathrm{V}_{\text {-. }} Timed Out knicks - Go... NFL Footba... Homework * 5: 9(1,3,4,5) 14(1,2) Question 10 of 30 (1 point) I Question Attempt: 1 of 3
Spam: A researcher reported that 71.8%71.8 \% of all email sent in a recent month was spam. A system manager at a large corporation believes that the percentage at his company may be 77%77 \%. He examines a random sample of 500 emails received at an email server, and finds that 364 of the messages are spam. Can you conclude that the percentage of emails that are spam differs from 77%77 \% ? Use both α=0.01\alpha=0.01 and α=0.05\alpha=0.05 levels of significance and the PP-value method with the TI-84 Plus calculator.
Part 1 of 5 (a) State the appropriate null and alternate hypotheses. H0:H1:\begin{array}{l} H_{0}: \square \\ H_{1}: \square \end{array}
This hypotheses test is a left-tailed \quad \nabla test.
Correct Answer: H0:p=0.77H1:p0.77\begin{array}{l} H_{0}: p=0.77 \\ H_{1}: p \neq 0.77 \end{array}
This hypotheses test is a two-tailed test.
Part: 1/51 / 5
Part 2 of 5 (b) Compute the value of the test statistic. Round the answer to at least two decimal places. z=z=\square

Studdy Solution
Calculate the test statistic z z using the formula:
z=p^p0SE z = \frac{\hat{p} - p_0}{\text{SE}}
z=0.7280.770.0188 z = \frac{0.728 - 0.77}{0.0188}
z=0.0420.01882.23 z = \frac{-0.042}{0.0188} \approx -2.23
The value of the test statistic is:
z2.23 z \approx -2.23

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