Math  /  Algebra

QuestionSolve the system by using Gaussian elimination or Gauss-Jordan elimination. 3(x3y)=10y10y=2x10\begin{aligned} -3(x-3 y) & =-10-y \\ 10 y & =-2 x-10 \end{aligned}
The solution set is \square \square 1)\}.

Studdy Solution
Verify the solution by substituting back into the original equations:
1. First equation:
3(03(1))=10(1)-3(0 - 3(-1)) = -10 - (-1)
Simplify:
3(3)=9and10+1=9-3(3) = -9 \quad \text{and} \quad -10 + 1 = -9
Both sides are equal.
2. Second equation:
10(1)=2(0)1010(-1) = -2(0) - 10
Simplify:
10=10-10 = -10
Both sides are equal.
The solution is verified.
The solution set is (0,1)(0, -1).

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