QuestionSolve the following quadratic equation using the quadratic formula. $-4y^2 - 3y + 4 = 0$

Studdy Solution
The solutions to the equation $-4y^2 - 3y + 4 = 0$ are $y = \frac{-3 - \sqrt{73}}{8}$ and $y = \frac{-3 + \sqrt{73}}{8}$.