Math  /  Algebra

QuestionSolve x2a2y2b2=1\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1 for 'x' with no specific values for 'y', 'a', and 'b'.

Studdy Solution
Finally, we can simplify the expression under the square root by factoring out a2a^{2}.
x=±a1+y2b2x = \pm a\sqrt{1 + \frac{y^{2}}{b^{2}}}So, the solutions for 'x' are x=a1+y2b2x = a\sqrt{1 + \frac{y^{2}}{b^{2}}} and x=a1+y2b2x = -a\sqrt{1 + \frac{y^{2}}{b^{2}}}.

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