QuestionSolve the equation $$t^{2}+13 t+42=0$$

Studdy Solution
Solve each equation for $t$:
$$t + 6 = 0 \quad \Rightarrow \quad t = -6$$ $$t + 7 = 0 \quad \Rightarrow \quad t = -7$$
The solutions to the equation $t^2 + 13t + 42 = 0$ are:
$$t = -6 \quad \text{and} \quad t = -7$$