Math  /  Algebra

QuestionSolve the equation. 62(a+1)=7+aa=\begin{array}{l} 6-2(a+1)=7+a \\ a=\square \end{array}

Studdy Solution
Verify the solution by substituting a=1 a = -1 back into the original equation:
Original equation: 62(a+1)=7+a 6 - 2(a+1) = 7 + a
Substitute a=1 a = -1 :
62(1+1)=7+(1) 6 - 2(-1+1) = 7 + (-1)
Simplify both sides:
62(0)=71 6 - 2(0) = 7 - 1
6=6 6 = 6
Both sides are equal, confirming that the solution is correct.
The solution is:
a=1 a = \boxed{-1}

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