Math  /  Algebra

QuestionSolve for xx in the equation: 2+log3(2x+5)log3x=42+\log _{3}(2x+5)-\log _{3}x=4.

Studdy Solution
Finally, we will solve for 'x' by dividing both sides of the equation by '7'.
x=57x=\frac{5}{7}So, the solution to the equation is x=57x=\frac{5}{7}.

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