QuestionSolve for $x$ : $$\begin{array}{l} \log (x+3)-\log (x+1)=1 \\ x=\square \end{array}$$
You may enter the exact value or round to 4 decimal places.

Studdy Solution
Rearrange the terms to solve for $x$. Subtract $x$ from both sides:
$3 = 9x + 10$
Subtract 10 from both sides:
$3 - 10 = 9x$
$-7 = 9x$
Divide both sides by 9:
$x = -\frac{7}{9}$
The value of $x$ is:
$x = -\frac{7}{9} \approx -0.7778$