Math / AlgebraQuestionSolve for xxx in the equation x2+2x+1=17x^{2}+2 x+1=17x2+2x+1=17 x=−1±15x=-1 \pm \sqrt{15}x=−1±15 x=−1±17x=-1 \pm \sqrt{17}x=−1±17 x=−2±25x=-2 \pm 2 \sqrt{5}x=−2±25 x=−1±13x=-1 \pm \sqrt{13}x=−1±13Studdy SolutionSo, our solutions for xxx are x=−1+17x = -1 + \sqrt{17}x=−1+17 and x=−1−17x = -1 - \sqrt{17}x=−1−17.This matches the second option!View Full Solution - FreeWas this helpful?