Math  /  Algebra

QuestionSolve for xx in terms of kk. 0/1 pt log7x+log7(x+9)=kx=\begin{array}{l} \log _{7} x+\log _{7}(x+9)=k \\ x=\square \end{array}
Find xx if k=2k=2. \square Question Help: Video Submit Question

Studdy Solution
In terms of kk, we have x=9+81+47k2x = \frac{-9 + \sqrt{81 + 4 \cdot 7^k}}{2}.
When k=2k=2, we have x=9+2772x = \frac{-9 + \sqrt{277}}{2}.

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