Math  /  Algebra

QuestionSolve: 243y=(1243)3y92y243^{-y}=\left(\frac{1}{243}\right)^{3 y} \cdot 9^{-2 y} y=1y=-1 y=0y=0 y=1y=1 no solution

Studdy Solution
So, the value of yy that makes the equation true is y=0y = 0!

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