QuestionSkill Practice 3 Write an equation of the line passing through the point $(-3,2)$ and parallel to the line defined by $x+3 y=6$. Write the answer in slope-intercept form and in standard form. Answer $$y=-\frac{1}{3} x+1 ; x+3 y=3$$

Studdy Solution
Convert the equation from slope-intercept form to standard form. Start with $y = -\frac{1}{3}x + 1$.
$$y = -\frac{1}{3}x + 1$$ $$3y = -x + 3$$ $$x + 3y = 3$$
So, the standard form of the equation is $x + 3y = 3$.
Solution: $$y = -\frac{1}{3}x + 1$$ $$x + 3y = 3$$