Math / AlgebraQuestionSimplify [(mn)2−1]÷(m/n+1)\left[\left(\frac{m}{n}\right)^{2}-1\right] \div\left(m/n + 1\right)[(nm)2−1]÷(m/n+1).Studdy SolutionFinally, we multiply the two fractions together.m2−n2n2×mm+n=m(m2−n2)n2(m+n)\frac{m^2-n^2}{n^2} \times\frac{m}{m+n} = \frac{m(m^2-n^2)}{n^2(m+n)}n2m2−n2×m+nm=n2(m+n)m(m2−n2)The simplified expression is m(m2−n2)n2(m+n)\frac{m(m^2-n^2)}{n^2(m+n)}n2(m+n)m(m2−n2). View Full Solution - FreeWas this helpful?