Math  /  Algebra

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12/21 Simplify: (2a3b4c3)2(4a2bc3)\left(2 a^{3} b^{4} c^{3}\right)^{2} \cdot\left(4 a^{2} b c^{3}\right)

Studdy Solution
Combine like terms using the laws of exponents:
=(44)(a6a2)(b8b)(c6c3)= (4 \cdot 4) \cdot (a^{6} \cdot a^{2}) \cdot (b^{8} \cdot b) \cdot (c^{6} \cdot c^{3})
Calculate each part:
=16a8b9c9= 16 \cdot a^{8} \cdot b^{9} \cdot c^{9}
The simplified expression is:
16a8b9c9\boxed{16 a^{8} b^{9} c^{9}}

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