Math  /  Algebra

QuestionСедедгөений бодлогууд Толын хоер зогсоолын хооронддл зай 60 км богоод моторт завь энэ зайг урегал дагуу 2 цатт, сорж 3 даг тудддаг. Моторт завины уурд болон урсгалын дурдыг ол.

Studdy Solution
Solve the system of equations.
First, simplify the equations:
1. 2(b+c)=60 2(b + c) = 60 becomes b+c=30 b + c = 30
2. 3(bc)=60 3(b - c) = 60 becomes bc=20 b - c = 20

Now, solve the system of equations:
Add the two equations:
(b+c)+(bc)=30+20 (b + c) + (b - c) = 30 + 20 2b=50 2b = 50 b=25 b = 25
Substitute b=25 b = 25 into one of the original equations, for example, b+c=30 b + c = 30 :
25+c=30 25 + c = 30 c=5 c = 5
The speed of the motorboat in still water is 25 \boxed{25} km/h, and the speed of the current is 5 \boxed{5} km/h.

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