QuestionRewrite the following without an exponent. $$\left(\frac{8}{9}\right)^{-1}$$

Studdy Solution
Apply the rule for negative exponents to rewrite the expression:
$\left(\frac{8}{9}\right)^{-1} = \frac{1}{\left(\frac{8}{9}\right)^1}$
Since $\left(\frac{8}{9}\right)^1 = \frac{8}{9}$, we have:
$\frac{1}{\frac{8}{9}} = \frac{9}{8}$
Thus, the expression without an exponent is:
$\boxed{\frac{9}{8}}$