QuestionRewrite $\cot 28^{\circ}$ using its cofunction identity. $$\cot 28^{\circ} =$$

Studdy Solution
Subtract $28^{\circ}$ from $90^{\circ}$.
$$\cot28^{\circ} = \tan(90^{\circ} -28^{\circ}) = \tan(62^{\circ})$$So, $\cot28^{\circ}$ can be rewritten as $\tan62^{\circ}$ in terms of its cofunction.