Question$\left(r^{3}-6 r^{2}+11 r-10\right) \div(r-1)$

Studdy Solution
Interpret the result of the synthetic division:
The numbers in the bottom row represent the coefficients of the quotient polynomial. Since the original polynomial was of degree 3, the quotient will be of degree 2.
Thus, the quotient is:
$$r^2 - 5r + 6$$
The remainder is $-4$, so the complete division result is:
$$r^2 - 5r + 6 - \frac{4}{r-1}$$