Math  /  Calculus

QuestionQuestion 9 1 pts
Use the Alternating Series Estimation Theorem to find the minimum number of terms of the infinite series n=12(1)nn3\sum_{n=1}^{\infty} \frac{2(-1)^{n}}{n^{3}} we need to add to approximate the sum of the series with \mid error .016\mid \leq .016. 8 10 4 6

Studdy Solution
Solve the inequality 2(n+1)30.016\frac{2}{(n+1)^3} \leq 0.016:
1. Multiply both sides by (n+1)3(n+1)^3: $ 2 \leq 0.016(n+1)^3 \]
2. Divide both sides by 0.0160.016: $ \frac{2}{0.016} \leq (n+1)^3 \]
3. Calculate 20.016=125\frac{2}{0.016} = 125.
4. Take the cube root of both sides: $ n+1 \geq \sqrt[3]{125} = 5 \]
5. Solve for nn: $ n \geq 4 \]
Since nn must be an integer, the minimum nn is 4.
The minimum number of terms required is:
4 \boxed{4}

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