Math / CalculusQuestionQuestion 8. Find the derivatives of the following functions: y=sec(xx2+2)y=\sec \left(x \sqrt{x^{2}+2}\right)y=sec(xx2+2)Studdy SolutionThe derivative of y=sec(xx2+2)y = \sec\left(x\sqrt{x^2 + 2}\right)y=sec(xx2+2) is: dydx=sec(xx2+2)tan(xx2+2)⋅2(x2+1)x2+2 \frac{dy}{dx} = \sec\left(x\sqrt{x^2 + 2}\right)\tan\left(x\sqrt{x^2 + 2}\right) \cdot \frac{2(x^2 + 1)}{\sqrt{x^2 + 2}} dxdy=sec(xx2+2)tan(xx2+2)⋅x2+22(x2+1)View Full Solution - FreeWas this helpful?