Math  /  Data & Statistics

QuestionQuestion 6, 9.1.15 HW Score: 55.56%,555.56 \%, 5 of 9 points .1
Construct a 90%90 \% confidence interval of the population proportion using the given information. x=125,n=250x=125, n=250
Click here to view the table of critical values.
The lower bound is \square The upper bound is \square (Round to three decimal places as needed. Table of critical values \begin{tabular}{ccc} \begin{tabular}{c} Level of Confidence, \\ (1α)100%(\mathbf{1}-\alpha) \cdot \mathbf{1 0 0} \% \end{tabular} & Area in Each Tail, α2\frac{\boldsymbol{\alpha}}{\mathbf{2}} & Critical Value, zα2\boldsymbol{z}_{\frac{\boldsymbol{\alpha}}{\mathbf{2}}} \\ \hline 90%90 \% & 0.05 & 1.645 \\ \hline 95%95 \% & 0.025 & 1.96 \\ \hline 99%99 \% & 0.005 & 2.575 \\ \hline \end{tabular} Print Done

Studdy Solution
Construct the confidence interval:
Lower bound:
p^ME=0.50.052=0.448\hat{p} - ME = 0.5 - 0.052 = 0.448
Upper bound:
p^+ME=0.5+0.052=0.552\hat{p} + ME = 0.5 + 0.052 = 0.552
The lower bound is 0.448 \boxed{0.448} and the upper bound is 0.552 \boxed{0.552} .

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