QuestionQuestion 5 of 6 - /1 1 $z$ 3
A poll sampled 63 people, asking them their favorite skittle flavor by color (green, orange, purple, red, or yellow). A separate poll sampled 88 people, again asking them their favorite skittle flavor, but rather than by color they asked by the actual flavor (lime, orange, grape, strawberry, and lemon, respectively). The table below shows the results from both polls. Does the way people choose their favorite Skittles type, by color or flavor, appear to be related to which type is chosen? \begin{tabular}{lccccc} \hline & \begin{tabular}{c} Green \\ (Lime) \end{tabular} & \begin{tabular}{c} Purple \\ Orange \end{tabular} & \begin{tabular}{c} Red \\ (Grape) \end{tabular} & \begin{tabular}{c} Yellow \\ (Strawberry) \end{tabular} & \begin{tabular}{l} Lemon) \end{tabular} \\ \hline Color & 16 & 8 & 15 & 13 & 11 \\ Flavor & 13 & 16 & 20 & 31 & 8 \\ \hline \end{tabular}
Table 1 Skittles popularity (a) Give a table with the expected counts for each of the 10 cells.
Round your answers to one decimal place. \begin{tabular}{|c|c|c|c|c|c|} \hline & Green (Lime) & Orange & \begin{tabular}{l} Purple \\ (Grape) \end{tabular} & Red (Strawberry) & Yellow (Lemon) \\ \hline Color & i & i & i & i & i \\ \hline Flavor & i & i & i & i & i \\ \hline \end{tabular} (b) Are the expected counts large enough for a chi-square test? $\square$ (c) How many degrees of freedom do we have for this test?
Degrees of freedom $=$ $\square$ i (d) Calculate the chi-square test statistic.
Round your answer to two decimal places. chi-square statistic = $\square$ (e) Determine the $p$-value.
Round your answer to three decimal places. p-value $=$ $\square$