Math  /  Algebra

QuestionQuestion 3 of 10, Step 1 of 1 WILLIAM BURRIS 1/101 / 10 Correct
Use a system of equations to solve the following problem.
An investor decides to invest some cash in an account paying 6%6 \% annual interest, and to put the rest in a stock fund that ends up earning 9%9 \% over the course of a year. The investor puts $800\$ 800 more in the first account than in the stock fund, and at the end of the year finds the total interest from the two investments was $1950\$ 1950. How much money was invested at each of the two rates? Round to the nearest integer.
Answer How to enter your answer (opens in new window) Keypad Keyboard Shortcuts \ \squareat at 6 \%$ \$ \squareat at 9 \%$ Submit Answer

Studdy Solution
Round the solutions to the nearest integer if necessary. In this case, the solutions are already integers.
The amount invested at 6%6\% is:
\$ \boxed{13480}
The amount invested at 9%9\% is:
\$ \boxed{12680}

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