QuestionQuestion 2 (2 points) What is the daughter nuclide when Bi -214 experiences beta decay? (Write your answer as a symbol-mass number) $\square$ A

Studdy Solution
Determine the daughter nuclide:
- The atomic number of Bismuth (Bi) is 83. After beta decay, the atomic number increases to 84. - The element with atomic number 84 is Polonium (Po). - The mass number remains 214.
Thus, the daughter nuclide is $_{84}^{214}\text{Po}$.
The daughter nuclide is:
$$\boxed{\text{Po-214}}$$