QuestionQuestion 13 (1 point) Solve $2 \sin x+1=0$ on the interval $x \in[0,2 \pi]$, to the nearest hundredth of a radian. a) $x=210, x=330$ b) $x \doteq 0.52, x \doteq 2.62$ C) $x=30, x=150$ d) $x \doteq 3.67, x \doteq 5.76$

Studdy Solution
Convert these solutions to decimal form and round to the nearest hundredth:
$$x \approx 3.67 \, \text{radians}$$ $$x \approx 5.76 \, \text{radians}$$
The solutions to the equation $2 \sin x + 1 = 0$ on the interval $[0, 2\pi]$ are:
$$x \approx 3.67, x \approx 5.76$$
This corresponds to option d).