Math / AlgebraQuestionQ2 (6 pts). Given f(x)=7x2−6x+6,x≥3f(x)=7^{x^{2}-6 x+6}, x \geq 3f(x)=7x2−6x+6,x≥3. Find f−1(x)f^{-1}(x)f−1(x)Studdy SolutionExpress the inverse function:f−1(x)=6+12+4log7(x)2 f^{-1}(x) = \frac{6 + \sqrt{12 + 4\log_{7}(x)}}{2} f−1(x)=26+12+4log7(x) The inverse function f−1(x) f^{-1}(x) f−1(x) is:f−1(x)=6+12+4log7(x)2 f^{-1}(x) = \frac{6 + \sqrt{12 + 4\log_{7}(x)}}{2} f−1(x)=26+12+4log7(x)View Full Solution - FreeWas this helpful?
