Math / AlgebraQuestionQ.13) If f(x)=secxx+3f(x)=\frac{\sec x}{x+3}f(x)=x+3secx and f−1(c)=0\mathrm{f}^{-1}(\mathrm{c})=0f−1(c)=0, then c=\mathrm{c}=c= A. 13\frac{1}{3}31 B. 0 C. 23\frac{2}{\sqrt{3}}32 D. 14\frac{1}{4}41 E.NoneStuddy SolutionSince f(0)=c f(0) = c f(0)=c, we have:c=13 c = \frac{1}{3} c=31 The value of c c c is:13 \boxed{\frac{1}{3}} 31View Full Solution - FreeWas this helpful?
