Math  /  Algebra

QuestionPut the quadratic into vertex form and state the coordinates of the vertex. y=x26x+21y=x^{2}-6 x+21

Studdy Solution
Identify the vertex from the vertex form of the equation:
The vertex form is y=a(xh)2+k y = a(x-h)^2 + k , where (h,k) (h, k) is the vertex.
For y=(x3)2+12 y = (x - 3)^2 + 12 , the vertex is (h,k)=(3,12) (h, k) = (3, 12) .
The coordinates of the vertex are:
(3,12) \boxed{(3, 12)}

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