Math  /  Measurement

Question Show that for positive real numbers uu and vv, and a positive real number a1a \neq 1, loga(uv)=logaulogav\log_{a}\left(\frac{u}{v}\right) = \log_{a}u - \log_{a}v.

Studdy Solution
We have shown that loga(uv)\log _{a}\left(\frac{u}{v}\right) is indeed equal to logaulogav\log _{a} u - \log _{a} v, using the properties of logarithms and exponents.
This completes the proof.

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