Math  /  Calculus

QuestionProblem 3. Given a function f(x)=ex2+4xf(x)=e^{-x^{2}+4 x} (a) (6 points) find the minimum and maximum values attained by ff over an interval [0,3][0,3], (b) (2 points) find the equation of the tangent line to the graph of ff at a point (0,f(0))(0, f(0)).

Studdy Solution
(a) The **maximum value** of f(x)f(x) on the interval [0,3][0, 3] is e4e^4 at x=2x = 2, and the **minimum value** is 11 at x=0x = 0. (b) The equation of the tangent line at x=0x = 0 is y=4x+1y = 4x + 1.

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