QuestionIdentify the missing particle in the nuclear equation: $_{10}^{43} \mathrm{~K} \rightarrow{ }_{20}^{43} \mathrm{Ca}+?$

Studdy Solution
The atomic number Z = - and the mass number A =0. The particle with an atomic number of - and a mass number of0 is a beta particle (β-). So, the nuclear equation is$${ }_{19}^{43} \mathrm{~K} \rightarrow{ }_{20}^{43} \mathrm{Ca}+{ }_{-}^{0} \mathrm{β^-}$$So, the missing particle in the nuclear equation is a beta particle (β-).