QuestionFind the missing particle in the decay: ${ }_{84}^{218} \mathrm{Po} \rightarrow{ }_{2}^{4} \mathrm{He}+?$

Studdy Solution
Now that we have the atomic number and mass number of the unknown nucleus, we can identify it. The element with atomic number82 is lead (b). So the unknown nucleus is ${ }_{82}^{214} \mathrm{b}$.
So, the balanced nuclear equation is$${ }_{84}^{218} \mathrm{Po} \rightarrow { }_{2}^{4} \mathrm{He} + { }_{82}^{214} \mathrm{b}$$