Math  /  Data & Statistics

QuestionPart 1 of 4 omework
The claim is that smokers have a mean cotinine level greater than the level of 2.84ng/mL2.84 \mathrm{ng} / \mathrm{mL} found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n=869n=869 and the test statistic is t=53.714t=53.714. Use technology to find the PP-value. Based on the result, what is the final conclusion? Use a significance level of 0.05 .
State the null and alternative hypotheses. H0:μ\mathrm{H}_{0}: \mu \square \square H1:μ\mathrm{H}_{1}: \mu \square \square (Type integers or decimals. Do not round.)

Studdy Solution
Define the alternative hypothesis (H1H_1):
The alternative hypothesis claims that the mean cotinine level of smokers is greater than the level found for nonsmokers.
H1:μ>2.84 H_1: \mu > 2.84
The null and alternative hypotheses are:
H0:μ=2.84 H_0: \mu = 2.84 H1:μ>2.84 H_1: \mu > 2.84

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