Math  /  Algebra

Questionpq=(2i+jk)(i3j+2k)p \cdot q=(2 i+j-k)(i-3 j+2 k)

Studdy Solution
Add the calculated terms to obtain the final scalar value.
2+(3)+(2)=232=3 2 + (-3) + (-2) = 2 - 3 - 2 = -3
Solution: The dot product pqp \cdot q is:
(2i+jk)(i3j+2k)=3 (2i + j - k) \cdot (i - 3j + 2k) = -3

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