Math  /  Trigonometry

QuestionProve that 1cos2xsec2x1=1sin2x\frac{1-\cos ^{2} x}{\sec ^{2} x-1} = 1-\sin ^{2} x.

Studdy Solution
We know from the Pythagorean identity that cos2x=1sin2x\cos^2x =1 - \sin^2x.
1sin2x1 - \sin^2xThis is the same as the right side of the original equation, so the identity is verified.
1sin2x1sin2x1 - \sin^2x \equiv1 - \sin^2x

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