Math  /  Algebra

Question Minimize c=x+2y subject to x+3y285x+y28x0,y0c=(x,y)=(\begin{array}{c}\text { Minimize } c=x+2 y \text { subject to } \\ x+3 y \geq 28 \\ 5 x+y \geq 28 \\ x \geq 0, y \geq 0 \\ c= \\ (x, y)=(\end{array}

Studdy Solution
Identify the vertex that gives the minimum value of the objective function: - The minimum value of c c is 5.6 5.6 at (285,0) \left( \frac{28}{5}, 0 \right) .
Thus, the solution is: c=5.6at(x,y)=(285,0)c = 5.6 \quad \text{at} \quad (x, y) = \left( \frac{28}{5}, 0 \right)

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