Math  /  Algebra

QuestionRewrite the expression as a sum/difference of logarithms: log2(x4y6)\log _{2}\left(\frac{x^{4}}{y^{6}}\right)

Studdy Solution
Apply the power rule to both terms of the equation.
log2(x4)log2(y)=4log2(x)log2(y)\log{2}(x^{4}) - \log{2}(y^{}) =4 \cdot \log{2}(x) - \cdot \log{2}(y)So, the expression log2(x4y)\log{2}\left(\frac{x^{4}}{y^{}}\right) can be rewritten as 4log2(x)log2(y)4 \cdot \log{2}(x) - \cdot \log{2}(y).

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