Question$$\mathscr{L}\left\{e^{t+3}\right\}=$$
Select one: $e^{3 s} u(t+3)$ $\frac{e^{3}}{s-1}$ $\frac{1}{s+2}$ $\frac{1}{s-3}$

Studdy Solution
Compare the simplified result with the given options:
The correct answer is $\frac{e^3}{s-1}$.
The correct option is:
$$\boxed{\frac{e^3}{s-1}}$$