QuestionFind the conjugate $\bar{z}$ of the complex number $z=i^{2}(6-2 i)+8 i$ and express it as $a+bi$.

Studdy Solution
Finally, we write $\bar{z}$ in the form $a + bi$.
$$\bar{z} = -6 -10i$$The conjugate of the complex number $z=i^{2}(6-2 i)+8 i$ is $\bar{z} = -6 -10i$.