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Math  /  Algebra

QuestionFind the value of kk for each case:
19. 24k=1622^{4 k}=16^{2},
20. 28−3k=0.52^{8-3 k}=0.5,
21. 195k−3=119k−319^{5 k-3}=\frac{1}{19^{k-3}},
22. (16k)2=2162\left(\frac{1}{6^{k}}\right)^{2}=216^{2}.

Studdy Solution
Calculate the value of kk.
k=6−=−3k = \frac{6}{-} = -3The solutions for kk in each of the given equations are k=k =, k=3k =3, k=−k = -, and k=−3k = -3 respectively.

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